The number of permutations of alphabets of the word “ENSHRINE” in which no two alike alphabets are together is equal to

Question

MARKS Content Team · Accepted Answer

Correct answer: 5760. EENNSHRI Let the event E: E^(')s are together and event N: N's are together Required permutations=Total permutations -nE∪N =(8!)/(2!2!)-(7!)/(2!)+(7!)/(2!)-6! =10080-2520-2520+720=5760

The number of permutations of alphabets of the word “ENSHRINE” in which no two alike alphabets are together is equal to

Solution

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