Q58 / 160 · TS EAMCET 2023 (14 May Shift 2) · Mathematics

The number of odd numbers greater than $6,00,000$ that can be formed by using the digits $3,6,7,8,9,0$ without repetition is

A
480
Correct answer
B
240
C
288
D
500

Solution

$6,00,000$ odd integers using $3,6,7,8,9,0$ First place can be filled by $6,7,8,9$ and last place by $7,3,9$ Case 1: First place 6 or 8 $\begin{aligned} & \overline{2} \times \overline{4} \times \overline{3} \times \overline{2} \times \overline{1} \times \overline{3} \\ & =144 \text { ways }\end{aligned}$ Case 2: First place 7 or 9 Total $=144+96=240$ ways

Hence, the correct answer is option: 'B'.

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