Q12 / 160 · AP EAMCET 2013 · Chemistry

The number of octahedral and tetrahedral holes respectively present in a hexagonal close packed ( $h c p)$ crystal of ' $X$ ' atoms are

  • A
    $X, 2 X$
  • B
    $X, X$
  • Correct answer
    C
    $2 X, X$
  • D
    $2 X, 2 X$

Solution

In a close packed structure (hcp or $c c p)$ (i) Number of octahedral voids $=$ Number of particles present in the close packing (ii) Number of tetrahedral voids $=2 \times$ Number of octahedral voids.

Hence, the correct answer is option: 'C'.

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