Q17 / 125 · BITSAT 2013 · Chemistry

The number of enantiomers of the compound $\mathrm{CH}_{3} \mathrm{CHBrCHBrCOOH}$ is

  • A
    0
  • B
    1
  • C
    3
  • Correct answer
    D
    4

Solution

The structure $\mathrm{CH}_{3}{ }^{*} \mathrm{CH} \mathrm{Br} \mathrm{C}^{*} \mathrm{H} \mathrm{Br} \mathrm{COOH}$ has two different chiral carbon atoms, hence number of enantiomers (optically active forms) is $2^{n}=2^{2}=4$

Hence, the correct answer is option: 'D'.

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