Q34 / 160 · JIPMER 2014 · Botany

The net requirement of assimilatory power for the formation of 6 hexose molecules in maize plant is

  • A
    72 ATP, 48 NADPH
  • B
    90 ATP, 60 NADPH
  • C
    108 ATP, 72 NADPH
  • Correct answer
    D
    180 ATP, 72 NADPH

Solution

$\mathrm{C}_4$ plants (maize) require 30 ATP and 12 NADPH for synthesis of one hexose molecule. Therefore synthesis of six hexose molecules require 180 ATP and 72 NADPH.

Hence, the correct answer is option: 'D'.

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