Q31 / 250 · NTA Abhyas (NEET) 2020 · Physics · Electrostatics

The net force acting on $q_{0}$ is

A
$\frac{{kqq}_{0}}{\sqrt{2} a^{2}}$
B
$\frac{{kqq}_{0}}{{(a / 2)}^{2}}$
C
zero
Correct answer
D
$\frac{{kqq}_{0}}{a^{2}}$

Solution

Force due to (1), (2), (4) & (5) will cancel each other. Only force due to charge (3) will not get cancelled, hence

F_{Net} = \frac{{kqq}_{0}}{a^{2}}

.

Hence, the correct answer is option: 'D'.

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