Q141 / 180 · KCET 2009 · Physics

The moment of inertia of a circular ring of radius $\mathrm{r}$ and mass $\mathrm{M}$ about diameter is

A
$\frac{2}{5} \mathrm{Mr}^{2}$
B
$\frac{\mathrm{Mr}^{2}}{4}$
Correct answer
C
$\frac{\mathrm{Mr}^{2}}{2}$
D
$\frac{\mathrm{Mr}^{2}}{12}$

Solution

Moment of inertia of a circular ring about a diameter $\mathrm{I}=\frac{1}{2} \mathrm{Mr}^{2}$

Hence, the correct answer is option: 'C'.

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