Q40 / 180 · AIIMS 2017 · Chemistry

The $\mathrm{AsF}_5$ molecule is trigonal bipyramidal. The hybrid orbitals used by the As atoms for bonding are

  • A
    $d_{x^2-y^2}, d_{z^2}, s, p_x, p_y$
  • B
    $d_{x y}, s, p_x, p_y, p_z$
  • C
    $d_{x^2-y^2}, s, p_x, p_y$
  • Correct answer
    D
    $s, p_x, p_y, p_z, d_z^2$

Solution

$A_{s F_5}$ has $s p^3 d$ hybridisation. In $s p^3 d$ hybridisation, the $d_{z^2}$ orbital is used along with the ' $s$ ' and three ' $p$ ' orbitals to form three equatorial bonds and two equally strong axial bonds for a trigonal bipyramid.

Hence, the correct answer is option: 'D'.

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