The mole fraction of a solute in a 100 molal aqueous solution ________ ×10^(-2). (Round off to the Nearest Integer). [Given : Atomic masses: H :1.0 u…

Question

The mole fraction of a solute in a 100 molal aqueous solution ________ ×10^(-2). (Round off to the Nearest Integer). [Given : Atomic masses: H :1.0 u, O :16.0 u]

MARKS Content Team · Accepted Answer

Correct answer: 64. 100 molal aqueous solution means there is 100 mole solute in 1 kg=1000 gm water. Now, mole-fraction of solute=n_(solute )n_(solute )+n_(solvent ) =100/(100+100018)=1800/2800=0.6428 =64.28×10^(-2)

The mole fraction of a solute in a $100$ molal aqueous solution ________ $\times 10^{- 2} .$
(Round off to the Nearest Integer).
[Given : Atomic masses: $H : 1.0 u, O : 16.0 u$ ]

Solution

Relevant Questions

The mole fraction of a solute in a 100 molal aqueous solution ________ ×10-2.(Round off to the Nearest Integer).[Given : Atomic masses: H :1.0 u, O :16.0 u]

Solution

Relevant Questions

The mole fraction of a solute in a $100$ molal aqueous solution ________ $\times 10^{- 2} .$
(Round off to the Nearest Integer).
[Given : Atomic masses: $H : 1.0 u, O : 16.0 u$ ]