Q110 / 180 · NEET 2013 (All India) · Physics
The molar specific heats of an ideal gas at constant pressure and volume are denoted by $C_p$ and $C_V$ respectively. If $\gamma=\frac{C_p}{C_V}$ and $R$ is the universal gas constant, then $C_V$ is equal to
- A$\frac{1+\gamma}{1-\gamma}$
- Correct answerB$\frac{R}{(\gamma-1)}$
- C$\frac{(\gamma-1)}{R}$
- D$\gamma R$
Solution
The value of $C_V=\frac{R}{\gamma-1}$
Hence, the correct answer is option: 'B'.