Q110 / 180 · NEET 2013 (All India) · Physics

The molar specific heats of an ideal gas at constant pressure and volume are denoted by $C_p$ and $C_V$ respectively. If $\gamma=\frac{C_p}{C_V}$ and $R$ is the universal gas constant, then $C_V$ is equal to

  • A
    $\frac{1+\gamma}{1-\gamma}$
  • Correct answer
    B
    $\frac{R}{(\gamma-1)}$
  • C
    $\frac{(\gamma-1)}{R}$
  • D
    $\gamma R$

Solution

The value of $C_V=\frac{R}{\gamma-1}$

Hence, the correct answer is option: 'B'.

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