Q67 / 180 · KCET 2015 · Mathematics
The middle term of expansion of \( \left(\frac{10}{x}+\frac{x}{10}\right)^{10} \)
- A\( {}^{7} C_{5} \)
- B\( { }_{0}^{8} C_{5} \)
- C\( { }_{0}^{9} C_{5} \)
- Correct answerD\( { }^{10}{ }^{10} C_{5} \)
Solution
Given expression, \( \left(\frac{10}{x}+\frac{x}{10}\right)^{10} \)
here \( n=10 \). So, middle term is \( 6 \) th term
Therefore, \( T_{6}={ }^{10} C_{5}\left(\frac{10}{\chi}\right)^{5}\left(\frac{\chi}{10}\right)^{5}={ }^{10} C_{5} \)
here \( n=10 \). So, middle term is \( 6 \) th term
Therefore, \( T_{6}={ }^{10} C_{5}\left(\frac{10}{\chi}\right)^{5}\left(\frac{\chi}{10}\right)^{5}={ }^{10} C_{5} \)
Hence, the correct answer is option: 'D'.