Q31 / 77 · NTA Abhyas (JEE Main) 2020 · Chemistry · Solid State

The metal $M$ crystallizes in a body cantered lattice with cell edge $400 pm$ . The atomic radius of $M$ is

Correct answer: 173

Solution

a = 400 pm

In body central lattice

\sqrt{3} a = 4 r

r = \frac{\sqrt{3} a}{4}

r = \frac{\sqrt{3}}{4} \times 400

r = \sqrt{3} \times 100 = 173 p m

Hence, the correct answer is 173.

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