The mean momentum $p$ of a particle has uncertainty $\Delta p$. Taking Planck's constant to be $h$, the uncertainty in the de Broglie wavelength of the particle is

• A

  $\frac{h}{\Delta p}$
• B

  $\frac{h \Delta p}{p}$
• C

  $0$
• Correct answer
  D

  $\frac{h \Delta p}{p^2}$

Hence, the correct answer is option: 'D'.