Q89 / 180 · KCET 2015 · Mathematics

The mean deviation from the data $ 3,10,10,4,7,10,5 $ :

A
$ 03 $
B
$ 12 $
C
$ 3.75 $
Correct answer
D
$ 2.57 $

Solution

Given that, $\bar{x}=\frac{3+10+10+4+7+10+5}{7}-\frac{49}{7}=7$ Deviations is given by, $|3-7|=4,|10-7|=3,|10-7|=3$ $|4-7|=3,|7-7|=0,|10-7|=3,|5-7|=2$ So, mean deviation is given by, $\frac{4+3+3+3+0+3+2}{7}=\frac{18}{7}=2.57$

Hence, the correct answer is option: 'D'.

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The mean deviation from the data \( 3,10,10,4,7,10,5 \) :

Solution

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