Q109 / 160 · AP EAMCET 2021 (19 Aug Shift 2) · Mathematics

The maximum value of $f (x) = \sin (x)$ in the interval $[\frac{- π}{2}, \frac{π}{2}]$ is

A
$- 1$
B
$- 1$
Correct answer
C
$1$
D
$\sqrt{2}$

Solution

Drawing the curve of

$f (x) = \sin x$

We can see that at $x = \frac{π}{2}$ , we get maxima, which is the value $f (x) = 1 .$

Hence, the correct answer is option: 'C'.

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