Q1 / 160 · TS EAMCET 2022 (20 Jul Shift 1) · Chemistry

The maximum number of orbitals present in $n=4$ energy level of an atom and the maximum number of electrons with spin value $+\frac{1}{2}$ in the same orbitals are Figure
,respectively.

  • A
    16, 5
  • B
    16, 7
  • C
    16, 9
  • Correct answer
    D
    16, 16

Solution

For $\mathrm{n}=4 l=0,1,2,3$. For each ' $l$ ' value $(2 l+l)$ no. of orbitals are available. $$ l=0, \mathrm{~m}_l=1 ; l=1, \mathrm{~m}_l=3 ; l=2, \mathrm{~m}_l=5 ; l=3, \mathrm{~m}_l=7 $$ $\therefore \quad$ Total no. of orbitals $=1+3+5+7=16$ Each orbital contains maximum 2 electrons having spin value $\left(\ell+\frac{1}{2}\right)$ and $\left(-\frac{1}{2}\right)$. $\therefore \quad 16$ orbitals have 32 electrons among which 16 electrons have 2 spin value $\left(+\frac{1}{2}\right)$

Hence, the correct answer is option: 'D'.

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