Q141 / 200 · NEET 2003 · Physics

The mass of proton is $1.0073 u$ and that of neutron is $1.0087 u(u=$ atomic mass unit). The binding energy of ${ }_2^4 \mathrm{He}$ is: (Given helium nucleus mass $\approx 4.0015$ u)

A
$0.0305 \mathrm{~J}$
B
$0.0305 \mathrm{erg}$
Correct answer
C
$28.4 \mathrm{Me} \mathrm{V}$
D
$0.061 \mathrm{u}$

Solution

$\mathrm{BE}=4 m \times 931$ $=[2(1.0087+1.0073)-4.0015] \times$ 931 $=28.4 \mathrm{MeV}$.

Hence, the correct answer is option: 'C'.

Relevant Questions

Consider the following nuclear reaction : Take masses of , and as u, u and u, respectively. The Q value for the reaction, in keV, is : [Give2026 (Re-NEET)Nuclear energy
A nucleus with mass number 240 breaks into two fragments each of mass number 120 , the binding energy per nucleon of unfragmented nuclei is 2021Nuclear energy
The energy equivalent of 0.5 g of a substance is:2020 (Phase 1)Nuclear energy
The Binding energy per nucleon of L i 3 7 and H e 2 4 nucleon are 5.60 M e V and 7.06 M eV , respectively. In the nuclear reaction 3 7 L i +2014Nuclear energy
How does the Binding Energy per nucleon vary with the increase in the number of nucleons?2013 (Karnataka)Nuclear energy
A radioactive nucleus of mass emits a photon of frequency and the nucleus recoils. The recoil energy will be2011 (Screening)Nuclear energy