Q37 / 38 · NTA Abhyas (JEE Main) 2020 · Physics · Experimental Physics

The main scale of a vernier calliper reads in mm and its vernier scale is divided into 8 divisions, which coincides with 7 divisions of the main scale. It was also observed that, when the two jaws are brought in contact, the zero of the vernier scale coincided with the zero of the main scale. The edge length of a cube is measured using this vernier calliper. The main scale reads 12 mm and the 2nd division of the vernier scale coincides with the main scale. The edge length (in mm) of the cube is

Correct answer: 12.25

Solution

8 VSD = 7 MSD

⇒1 VSD = 78 MSD

LC = 1 MSD - 1 VSD

LC = 1 MSD - 78 MSD = 18 MSD = 18 mm

l = 12 + 2×18=12.25 mm

Hence, the correct answer is 12.25.

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