Q144 / 160 · AP EAMCET 2024 (22 May Shift 2) · Physics

The magnitude of an electric field which can just suspend a deuteron of mass $3.2 \times 10^{-27} \mathrm{~kg}$ freely in air is

Correct answer
A
$19.6 \times 10^{-8} \mathrm{NC}^{-1}$
B
$196 \mathrm{NC}^{-1}$
C
$1.96 \times 10^{-10} \mathrm{NC}^{-1}$
D
$0.196 \mathrm{NC}^{-1}$

Solution

$\mathrm{m}=3.2 \times 10^{-27} \mathrm{~kg}, \mathrm{q}=\mathrm{e}=1.6 \times 10^{-19} \mathrm{C}$ At equilibrium, $m g=qE$ $\Rightarrow \mathrm{E}=\frac{\mathrm{mg}}{\mathrm{q}}=\frac{3.2 \times 10^{-27} \times 9.8}{1.6 \times 10^{-19}}=19.6 \times 10^{-8} \mathrm{NC}^{-1}$

Hence, the correct answer is option: 'A'.

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