The magnitude and direction of the current in the circuit shown will be

• A

  $7 / 3$ A from a to $\mathrm{b}$ through $\mathrm{e}$
• B

  $7 / 3 \mathrm{~A}$ from $\mathrm{b}$ to a through $\mathrm{e}$
• C

  $1 \mathrm{~A}$ from $\mathrm{b}$ to a through $\mathrm{e}$
• Correct answer
  D

  $1 \mathrm{~A}$ from a to b through $\mathrm{e}$

Solution

The current in the circuit will be clockwise Since $\mathrm{E}_{1}(10 \mathrm{~V})>\mathrm{E}_{2}(4 \mathrm{~V})$
Applying Kirchhoff's junction rule $$ \begin{array}{l} -1 \times i-10-4 \times-2 \times i-3 i=0 \\ i=1 \mathrm{~A} \quad \text { (a to b via e) } \end{array} $$ Current $\mathrm{I}=\frac{V}{R}=\frac{10-4}{6}=1 \mathrm{~A}$

Hence, the correct answer is option: 'D'.