Q140 / 150 · MHT CET 2022 (10 Aug Shift 2) · Physics

The magnetic susceptibility of a material of a rod is 349 and permeability of vacuum $\mu_0$ is $4 \pi \times 10^{-7} \mathrm{SI}$ units. Absolute permeability of the material of the rod in SI units

  • A
    $4200 \times 10^{-7}$
  • B
    $4600 \times 10^{-7}$
  • Correct answer
    C
    $4400 \times 10^{-7}$
  • D
    $4800 \times 10^{-7}$

Solution

Given: $\mu_0=4 \pi \times 10^{-7} \mathrm{Hm}^{-1}$ Magnetic susceptibility of a material of rod: $\chi_{\mathrm{m}}=349$ $\therefore$ absolute permeability of material of rod: $\mu=\mu_0\left(1+\chi_{\mathrm{m}}\right)$ Or, $\mu=4 \pi \times 10^{-7}(1+349)=43982.3 \times 10^{-4} \mathrm{Hm}^{-1} \approx 4400 \times 10^{-7} \mathrm{Hm}^{-1}$

Hence, the correct answer is option: 'C'.

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