Q148 / 150 · MHT CET 2024 (09 May Shift 2) · Physics

The magnetic potential energy stored in certain inductor is $64 \times 10^{-3} \mathrm{~J}$, when the current in the inductor is 80 mA . This inductor is of inductance

  • A
    0.20 H
  • B
    2.0 H
  • Correct answer
    C
    20 H
  • D
    200 H

Solution

Energy stored in inductor, $\mathrm{E}=\frac{1}{2} \mathrm{LI}^2$ $\therefore \quad L=\frac{2 \mathrm{E}}{\mathrm{I}^2}=\frac{2 \times 64 \times 10^{-3}}{\left(80 \times 10^{-3}\right)^2}=20 \mathrm{H}$

Hence, the correct answer is option: 'C'.

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