Q12 / 90 · JEE Main 2019 (12 Jan Shift 2) · Chemistry

The magnetic moment of an octahedral homoleptic Mn(II) complex is 5.9 B.M. . The suitable ligand for this complex is:

  • A
    CN-
  • B
    CO
  • C
    Ethylenediamine
  • Correct answer
    D
    NCS-

Solution

Mn2+ will have configuration =3d54s0

μ=5.93=nn+2

or, n=5 as 35=5.93

If has 5 unpaired electron which are not getting paired up. This implies that the ligand paired up, and the ligand is a weak field ligand. Among the given options, weak ligand is NCS-

Hence, the correct answer is option: 'D'.

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