Q58 / 180 · KCET 2009 · Chemistry

The magnetic moment of a transition metal ion is $\sqrt{15}$ BM. Therefore, the number of unpaired electrons present in it, is

Correct answer
A
3
B
4
C
1
D
2

Solution

$\begin{array}{lrl}\mu=\sqrt{n(n+2)} & & \\ \Rightarrow & \sqrt{15} & =\sqrt{n(n+2)} \\ \therefore & n & =3\end{array}$

Hence, the correct answer is option: 'A'.

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