The magnetic moment and moment of inertia of a magnetic needle as shown are, respectively, 1.0 × 10^-2 ~A ~m and frac10^-6π^2 ~kg ~m^2 . If it…

Question

The magnetic moment and moment of inertia of a magnetic needle as shown are, respectively, $1.0 \times 10^{-2} \mathrm{~A} \mathrm{~m}$ and $\frac{10^{-6}}{\pi^2} \mathrm{~kg} \mathrm{~m}^2$. If it completes 10 oscillations in 10 s , the magnitude of the magnetic field is

MARKS Content Team · Accepted Answer

Correct answer: (C) 0.4 mT. Time period of oscillation of magnet inside the magnetic field T=2 π √(1/(M B)) T=t/n=10/10=1 ~s 1=2 π √frac10^-6π^2 × 1.0 × 10^-2 × B 1/4=frac10^-4B ⇒ B=0.4 mT

The magnetic moment and moment of inertia of a magnetic needle as shown are, respectively, $1.0 \times 10^{-2} \mathrm{~A} \mathrm{~m}$ and $\frac{10^{-6}}{\pi^2} \mathrm{~kg} \mathrm{~m}^2$. If it completes 10 oscillations in 10 s , the magnitude of the magnetic field is

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