Q151 / 160 · TS EAMCET 2022 (19 Jul Shift 2) · Physics

The magnetic flux through the triangular loop shown in the figure below: Figure
where a uniform magnetic field of strength $2 \mathrm{~T}$ points perpendicularly into the plane of the triangle.

  • A
    $10^{-4} \mathrm{~Wb}$
  • Correct answer
    B
    $2 \times 10^{-4} \mathrm{~Wb}$
  • C
    $1 \mathrm{~Wb}$
  • D
    $2 \mathrm{~Wb}$

Solution

$\begin{aligned} & \phi=\overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{A}} \\ & =\mathrm{BA} \cos 0^{\circ} \\ & =2 \times \frac{1}{2} \times 2 \times 1 \times 10^{-4} \\ & =2 \times 10^{-4} \mathrm{~Wb}\end{aligned}$

Hence, the correct answer is option: 'B'.

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