Q130 / 150 · MHT CET 2022 (07 Aug Shift 2) · Physics

The magnetic flux linked with the coil with time as $\Phi=4 \mathrm{t}^2+3 \mathrm{t}+7$. The magnitude of the induced e.m.f at $t=2 \mathrm{~s}$ is

  • Correct answer
    A
    $16 \mathrm{~V}$
  • B
    $29 \mathrm{~V}$
  • C
    $11 \mathrm{~V}$
  • D
    $19 \mathrm{~V}$

Solution

Given that Total magnetic flux $\phi=3 t^2+4 t+7$ We know that, The induced e.m.f $\mathrm{e}=\left|\frac{-\mathrm{d} \phi}{\mathrm{dt}}\right|=\frac{\mathrm{d}\left(3 \mathrm{t}^2+4 \mathrm{t}+7\right.}{\mathrm{dt}}=6 \mathrm{t}+4$ Now, the induced e.m.f at $\mathrm{t}=2 \mathrm{sec}$ $e=6 \times 2+4=16$ volt Hence, the magnitude of induced e.m.f is 16 volt

Hence, the correct answer is option: 'A'.

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