The magnetic field in a region is given by $\overrightarrow{B}=B_0\left(\frac{x}{a}\right)\hat{\mathrm{k}}$. A square loop of side d is placed with its edges along the $x$ and $y$ axes. The loop is moved with a constant velocity $\overrightarrow{v}=v_0\hat{\mathrm{i}}$. The emf induced in the loop is :

• A

  $\frac{B_0{v}_0^2 d}{2a}$
• B

  $\frac{B_0{v}_{0}d}{2a}$
• Correct answer
  C

  $\frac{B_0{v}_0{d}^2}{a}$
• D

  $\frac{B_0{v}_0{d}^2}{2a}$

Hence, the correct answer is option: 'C'.