Q152 / 160 · TS EAMCET 2020 (09 Sep Shift 2) · Physics
The magnetic field at point $P$ of given figure due to carrying of current $I$ by a conductor of radius $R$, is


- A$\frac{\mu_0 l}{4 \pi r} \mathrm{~T}$
- Correct answerB$\frac{\mu_0 l}{2 \pi r} \mathrm{~T}$
- C$\frac{\mu_0 l}{2 \pi R} T$
- D$\frac{\mu_0 I}{4 \pi R} \top$
Solution
Magnetic field due to a current carrying
conductor at an outside point is given by
$B=\frac{\mu_0 I}{2 \pi r} \mathrm{~T}$
Hence, the correct answer is option: 'B'.