The logic gate equivalent to given logic gate is

The inputs $A$ and $B$ are passed through NOT gates, giving outputs $\bar{A}$ and $\bar{B}$.

These outputs are fed into a NOR gate. The Boolean expression for the final output $Y$ is:

$Y = \overline{\bar{A} + \bar{B}}$

Using De Morgan's theorem, $\overline{X + Y} = \bar{X} \cdot \bar{Y}$:

$Y = \overline{\bar{A}} \cdot \overline{\bar{B}}$

$Y = A \cdot B$

This represents the Boolean expression for an AND gate.

Answer: AND Gate