Q98 / 160 · AP EAMCET 2018 (24 Apr Shift 2) · Mathematics

The locus of the point of intersection of the tangents drawn at the extremities of a normal chord of the hyperbola $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ is

  • A
    $\frac{a^2}{x^2}-\frac{b^2}{y^2}=a^2+b^2$
  • B
    $\frac{a^4}{x^2}-\frac{b^4}{y^2}=\left(a^2-b^2\right)^2$
  • C
    $\frac{a^3}{x^2}-\frac{b^3}{y^2}=\left(a^2+b^2\right)^2$
  • Correct answer
    D
    $\frac{a^6}{x^2}-\frac{b^6}{y^2}=\left(a^2+b^2\right)^2$

Hence, the correct answer is option: 'D'.

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