Q98 / 160 · AP EAMCET 2018 (24 Apr Shift 2) · Mathematics
The locus of the point of intersection of the tangents drawn at the extremities of a normal chord of the hyperbola $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ is
- A$\frac{a^2}{x^2}-\frac{b^2}{y^2}=a^2+b^2$
- B$\frac{a^4}{x^2}-\frac{b^4}{y^2}=\left(a^2-b^2\right)^2$
- C$\frac{a^3}{x^2}-\frac{b^3}{y^2}=\left(a^2+b^2\right)^2$
- Correct answerD$\frac{a^6}{x^2}-\frac{b^6}{y^2}=\left(a^2+b^2\right)^2$
Hence, the correct answer is option: 'D'.