The locus of the midpoint of the chords of the hyperbola x^225-y^236=1 which passes through the point 2,4 is a hyperbola, whose transverse axis length…

Question

The locus of the midpoint of the chords of the hyperbola x^225-y^236=1 which passes through the point 2,4 is a hyperbola, whose transverse axis length (in units) is equal to

MARKS Content Team · Accepted Answer

Correct answer: (A) 16/5. The equation of the chord whose mid-point is (h,k) is T=S_1 ⇒xh/25-yk/36=h^225-k^236 Since it passes through 2,4 2h/25-4k/36=h^225-k^236⇒(h^2-2h+1)/25-(k^2-4k+4)/36=1/25-4/36 Hence, the locus of h,k is x-1^216/9-y-2^264/25=-1 This is the equation of a hyperbola whose transverse axis length is 16/5 units

The locus of the midpoint of the chords of the hyperbola $\frac{x^{2}}{25} - \frac{y^{2}}{36} = 1$ which passes through the point $(2, 4)$ is a hyperbola, whose transverse axis length (in units) is equal to

Solution

More Hyperbola Questions

The locus of the midpoint of the chords of the hyperbola x225-y236=1 which passes through the point 2,4 is a hyperbola, whose transverse axis length (in units) is equal to

Solution

More Hyperbola Questions

The locus of the midpoint of the chords of the hyperbola $\frac{x^{2}}{25} - \frac{y^{2}}{36} = 1$ which passes through the point $(2, 4)$ is a hyperbola, whose transverse axis length (in units) is equal to