Q84 / 180 · COMEDK 2016 · Mathematics
The lines represented by $a x^{2}+2 h x y+b y^{2}=0$ are perpendicular to each other if
- A$h=0$
- B$h^{2}=a b$
- Correct answerC$a+b=0$
- D$h^{2}=a+b$
Solution
We know that the angle between the two lines
$a x^{2}+2 h x y+b y^{2}=0$ is given by
$\tan \theta=\left|\frac{2 \sqrt{h^{2}-a b}}{a+b}\right|$
$\begin{aligned} \because & \theta &=90^{\circ} \\ & \therefore & a+b &=0 \end{aligned}$
Hence, the correct answer is option: 'C'.