Q85 / 160 · AP EAMCET 2006 · Mathematics

The lines $x-y-2=0, x+y-4=0$ and $x+3 y=6$ meet in the common point :

  • A
    $(1,2)$
  • B
    $(2,2)$
  • Correct answer
    C
    $(3,1)$
  • D
    $(1,1)$

Solution

The equation of lines are $x-y-2=0$ ...(i) $x+y-4=0$ ...(ii) and $\quad x+3 y=6$ ...(iii) On solving Eqs. (i) and (ii), we get $x=3, y=1$ On putting these value in Eq. (iii) $3+3=6$ which is satisfied. Thus the required point is $(3,1)$.

Hence, the correct answer is option: 'C'.

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