The line $4 x-3 y+2=0$ intersects the circle $x^2+y^2-2 x+6 y+c=0$ at two points A, B and $\mathrm{AB}=8$. If $(1, \mathrm{k})$ is a point on the given circle and $\mathrm{k}>0$, then $\mathrm{k}=$

• A

  8
• B

  4
• Correct answer
  C

  2
• D

  1

Hence, the correct answer is option: 'C'.