Q94 / 160 · TS EAMCET 2006 · Mathematics

The length of the tangent drawn to the circle $x^2+y^2-2 x+4 y-11=0$ from the point $(1,3)$ is :

  • A
    1
  • B
    2
  • Correct answer
    C
    3
  • D
    4

Solution

The length of the tangent drawn to the circle $x^2+y^2-2 x+4 y-11=0$ from the point $(1,3)$ $=\sqrt{1^2+3^2-2 \cdot 1+12-11}$ $=\sqrt{1+9-2+12-11}$ $=\sqrt{22-13}=\sqrt{9}$ $=3$

Hence, the correct answer is option: 'C'.

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