Q36 / 90 · JEE Main 2019 (10 Jan Shift 2) · Mathematics

The length of the chord of the parabola x2=4y having equation x-2y+42=0 is

  • Correct answer
    A
    63 units
  • B
    82 units
  • C
    211 units
  • D
    32 units

Solution

Solving the equations of the given parabola and the line, we get,

2y-422=4y⇒y2-10y+16=0

⇒y1-y2=y1+y22-4y1y2=100-64=6

Figure

⇒ Length of the chord =AB=x1-x22+y1-y22=2y1-y22+y1-y22=3y1-y2

=63 units

Hence, the correct answer is option: 'A'.

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