The IUPAC name of the compound

is ________.

• Correct answer
  A

  3-Keto-2-methylhex-4-enal
• B

  5-Formylhex-2-en-3-one
• C

  5-Methyl-4-oxohex-2-en-5-al
• D

  3-Keto-2-methylhex-5-enal

Solution

Aldehydes get higher priority over ketone and alkene in numbering of principal C-chain.

$\therefore$ 3-Keto-2-methylhex-4-enal

Hence, the correct answer is option: 'A'.