Q124 / 180 · KCET 2007 · Physics

The ionisation energy of $\mathrm{Li}^{2+}$ is equal to

  • Correct answer
    A
    $9 h c R$
  • B
    $6 h c R$
  • C
    $2 h c R$
  • D
    $h c R$

Solution

Ionization energy $=R c h Z^{2}$ $$ Z=3 \text { for } \mathrm{Li}^{2+} $$ $\therefore$ Ionization energy $=(3)^{2} R c h=9 R c h$

Hence, the correct answer is option: 'A'.

Relevant Questions