Q124 / 180 · KCET 2007 · Physics
The ionisation energy of $\mathrm{Li}^{2+}$ is equal to
- Correct answerA$9 h c R$
- B$6 h c R$
- C$2 h c R$
- D$h c R$
Solution
Ionization energy $=R c h Z^{2}$
$$
Z=3 \text { for } \mathrm{Li}^{2+}
$$
$\therefore$ Ionization energy $=(3)^{2} R c h=9 R c h$
Hence, the correct answer is option: 'A'.