Q4 / 90 · JEE Main 2019 (08 Apr Shift 2) · Chemistry

The ion that has ${s p}^{3} d^{2}$ hybridization for the central atom is:

Solution

Steric number $= σ + l p$ $= 4 + 2;$ $s p^{3} d^{2}$ hybridized

Steric number $= σ + l p$ $= 2 + 3 = 5;$ $s p^{3} d$ hybridized

Steric number $= σ + l p$ $= 6 + 1 = 7;$ $s p^{3} d^{3}$ hybridized

Steric number $= σ + l p$ $= 2 + 3 = 5;$ $s p^{3} d$ hybridized

Hence, the correct answer is option: 'B'.