Q13 / 125 · BITSAT 2009 · Chemistry
The intermediate formed during the addition of $\mathrm{HCl}$ to propene in the presence of peroxide is
- A$\mathrm{CH}_{3} \mathrm{CHCH}_{2} \mathrm{CI}$
- Correct answerB$\mathrm{CH}_{2} \mathrm{CHCH}_{3}$
- C$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2}$
- D$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{C} \mathrm{H}_{2}$
Solution
The addition of HCl to propene proceeds by ionic mechanism and not by free radical mechanism. Hence it forms intermediate carbonium ion.
Hence, the correct answer is option: 'B'.