Q128 / 180 · NEET 2025 · Physics

The intensity of transmitted light when a polaroid sheet, placed between two crossed polaroids at $22.5^{\circ}$ from the polarization axis of one of the polaroid, is ( $\mathrm{I}_0$ is the intensity of polarised light after passing through the first polaroid):

  • A
    $\frac{\mathrm{I}_0}{2}$
  • B
    $\frac{\mathrm{I}_0}{4}$
  • Correct answer
    C
    $\frac{\mathrm{I}_0}{8}$
  • D
    $\frac{\mathrm{I}_0}{16}$

Solution

Initially two polaroids are crossed i.e. $90^{\circ}$ Figure
After passing from first polaroid intensity is $\mathrm{I}_0$Figure
$\begin{aligned} & \Rightarrow \frac{\mathrm{I}_0}{4} \sin ^2(2 \theta) \\ & \Rightarrow \frac{\mathrm{I}_0}{4} \sin ^2(2 \times 22.5) \\ & \Rightarrow \frac{\mathrm{I}_0}{8}\end{aligned}$

Hence, the correct answer is option: 'C'.

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