Q52 / 150 · MHT CET 2020 (20 Oct Shift 2) · Mathematics
The integrating factor of the differential equation $\frac{d y}{d x}(x \log x)+y=4 \log x$ is
- A$\log (\log x)$
- B$x$
- C$e^{x}$
- Correct answerD$\log x$
Solution
We have $\frac{d y}{d x}(x \log x)+y \quad=4 \log x$
$\therefore \frac{d y}{d x}+\left(\frac{1}{x \log x}\right) y=\frac{4}{x}$
$\therefore$ I.F. $=e^{\int \frac{d x}{x \log x}}=e^{\log (\log x)}=\log x$
Hence, the correct answer is option: 'D'.