The initial speed of a projectile fired from ground is u. At the highest point during its motion, the speed of projectile is √32u. The time of flight…

Question

The initial speed of a projectile fired from ground is u. At the highest point during its motion, the speed of projectile is √32u. The time of flight of the projectile is:

MARKS Content Team · Accepted Answer

Correct answer: (B) u/g. At maximum height, only horizontal velocity of the particle remains. Let the angle of project be θ. The horizontal velocity of the particle will remain same, therefore ucosθ=(√3u)/2⇒θ=30° Now, time of flight of projectile is T=(2usinθ)/g=u/g

The initial speed of a projectile fired from ground is $u$ . At the highest point during its motion, the speed of projectile is $\frac{\sqrt{3}}{2} u$ . The time of flight of the projectile is:

Solution

Relevant Questions

The initial speed of a projectile fired from ground is u. At the highest point during its motion, the speed of projectile is 32u. The time of flight of the projectile is:

Solution

Relevant Questions

The initial speed of a projectile fired from ground is $u$ . At the highest point during its motion, the speed of projectile is $\frac{\sqrt{3}}{2} u$ . The time of flight of the projectile is: