The initial rates of decrease of $\mathrm{I}_2$ in acetone - iodine reaction catalysed by $\mathrm{H}^{+}$ are given in the table. $\begin{array}{|c|c|c|c|c|} \hline \begin{array}{c} \text { Experiment } \\ \end{array} & \begin{array}{c} \text { Initial } \\ {\left[\mathrm{I}_2\right]} \\ \left(\mathrm{mol} \mathrm{L}^{-1}\right) \end{array} & \begin{array}{c} \text { Initial } \\ {\left[\mathrm{H}^{+}\right]} \\ \left(\mathrm{mol} \mathrm{L}^{-1}\right) \end{array} & \begin{array}{c} \text { Initial } \\ {\left[\mathrm{CH}_3 \mathrm{COCH}_3\right]} \\ \left(\mathrm{mol} \mathrm{L}^{-1}\right) \end{array} & \begin{array}{c} \text { Initial rate of decrease of } \mathrm{I}_2 \\ \left(\mathrm{mol} \mathrm{L}^{-1} \mathrm{~s}^{-1}\right) \end{array} \\ \hline 1 & 0.01 & 0.1 & 0.1 & 0.096 \\ 2 & 0.01 & 0.2 & 0.1 & 0.192 \\ 3 & 0.02 & 0.2 & 0.1 & 0.192 \\ 4 & 0.01 & 0.2 & 0.2 & 0.384 \\ \hline \end{array}$ The order with respect to $\mathrm{I}_2, \mathrm{H}^{+}$, acetone and total order of the reaction respectively are:

• A

  $0,2,1,3$
• B

  $1,0,1,2$
• Correct answer
  C

  $0,1,1,2$
• D

  $1,1,0,2$

Hence, the correct answer is option: 'C'.