Q110 / 150 · MHT CET 2010 · Physics

The increase in pressure required to decrease the $200 \mathrm{~L}$ volume of a liquid by $0.008 \%$ in $\mathrm{kPa}$ is (Bulk modulus of the liquid $=2100 \mathrm{MPa}$ is )

  • A
    $8.4$
  • Correct answer
    B
    84
  • C
    $92.4$
  • D
    168

Solution

Bulk modulus $K=\frac{\Delta p}{\Delta V} \cdot V$ $$ \begin{array}{l} \Delta p=\frac{K \Delta V}{V} \\ \Delta p=\frac{2100 \times 10^{6} \times 0.008}{200} \end{array} $$

Hence, the correct answer is option: 'B'.

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