Q11 / 160 · TS EAMCET 2019 (04 May Shift 2) · Chemistry

The increase in entropy in $\mathrm{JK}^{-1}$ of a substance when it absorbs $1 \mathrm{~kJ}$ of heat energy at $3 \mathrm{~K}$ is

  • A
    3.33
  • Correct answer
    B
    333.3
  • C
    0.333
  • D
    0.0333

Solution

Given, $$ \begin{aligned} & \text { Heat }(q)=1 \mathrm{~kJ}=1000 \mathrm{~J} \\ & \text { Temperature }=3 \mathrm{~K} \\ & \text { Entropy } \begin{aligned} (\Delta S) & =\frac{\text { Absorb heat }(q)}{\text { Temperature }(T)} \\ & =\frac{1000 \mathrm{~J}}{3 \mathrm{~K}} \end{aligned} \end{aligned} $$ Entropy $(S)=333.3 \mathrm{~J} / \mathrm{K}$

Hence, the correct answer is option: 'B'.

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