The hydrolysis of optically active \( 2 \)-bromobutane with aqueous \( \mathrm{NaOH} \) result in the formation of

• A

  \( (+) \) butan-2-ol
• B

  (-) butan-2-ol
• C

  ( \( \pm \) ) butan-1-ol
• Correct answer
  D

  ( \( \pm \) ) butan-2-ol

Solution

2-Bromobutane is a secondary alkyl halide, therefore, hydrolysis will proceed through \( S_{N} 1 \) mechanisms, hence, racemic
mixture will be formed, that is, (±) butan-2-ol.


(+) Butan-2-ol
(-) Butan-2-ol

Hence, the correct answer is option: 'D'.