Q30 / 90 · JEE Main 2024 (09 Apr Shift 1) · Chemistry

The heat of solution of anhydrous \(\mathrm{CuSO}_4\) and \(\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}\) are \(-70 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and \(+12 \mathrm{~kJ} \mathrm{~mol}^{-1}\) respectively. The heat of hydration of \(\mathrm{CuSO}_4\) to \(\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}\) is \(-x \mathrm{~kJ}\). The value of \(x\) is ______ (nearest integer).

Correct answer: 82

Solution

Figure
$\begin{gathered}\text { from }(1) \&(2) \\ -70=x+12 \\ x=-82\end{gathered}$

Hence, the correct answer is 82.

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