Q67 / 180 · NEET 2020 (Phase 2) · Chemistry

The half-life for a zero order reaction having $0.02 M$ initial concentration of reactant is $100 s$ . The rate constant (in $mol L^{- 1} s^{- 1}$ ) for the reaction is

Solution

${(t_{1 / 2})}_{zero} = \frac{[A]_{0}}{2 K}$

$100 s = \frac{0.02 M}{2 K}$
$K = \frac{0.02 M}{2 \times 100} = 1 \times 10^{- 4} mol L^{- 1} s^{- 1}$

Hence, the correct answer is option: 'A'.